22r^2-63r+20=0

Solution for 22r^2-63r+20=0 equation:

22r^2-63r+20=0

a = 22; b = -63; c = +20;
Δ = b2-4ac
Δ = -632-4·22·20
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-47}{2*22}=\frac{16}{44}
=4/11
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+47}{2*22}=\frac{110}{44}
=2+1/2
$